In an AC circuit, the voltage and current are given by V = 100 sin(100t) and I = 100 sin(100t + π/3). The power dissipated is
Q1. In an AC circuit, the voltage and current are given by V = 100 sin(100t) and I = 100 sin(100t + π/3). The power dissipated is
Answer: 2.5 kW
Explanation: P = V_rms * I_rms * cos(φ) = (100 / √2) * (100 / √2) * cos(π/3) = 2500 W = 2.5 kW.