engineering physics MCQ #884

A particle is moving in a circular path of radius 2 m with a constant speed of 4 m/s. What is its centripetal acceleration?

engineering physics MCQ #884

  1. Question 1

    Q1. A particle is moving in a circular path of radius 2 m with a constant speed of 4 m/s. What is its centripetal acceleration?

    • A) 4 m/s²
    • B) 6 m/s²
    • C) 8 m/s²
    • D) 10 m/s²

    Answer: 8 m/s²

    Explanation: Centripetal acceleration = v² / r = (4)² / 2 = 8 m/s², using the formula for centripetal acceleration.