An object is moving in a circular path. If its mass is doubled and speed is halved, what happens to its centripetal force?
Q1. An object is moving in a circular path. If its mass is doubled and speed is halved, what happens to its centripetal force?
Answer: It is reduced to 1/8
Explanation: Centripetal force = (m * v²) / r. When m is doubled and v is halved, force becomes (2m * (v/2)²) / r = 1/2 * m * v² / r, which is 1/8 of the original if considering the effect of mass and velocity change together, it actually results in (2 * (1/4)) = 1/2, so the correct interpretation should be: the new force is 1/2 of the original, my explanation requires correction.