engineering physics MCQ #900

What happens to the period of a circular motion if the radius is doubled and the speed remains constant?

engineering physics MCQ #900

  1. Question 1

    Q1. What happens to the period of a circular motion if the radius is doubled and the speed remains constant?

    • A) It is doubled
    • B) It is halved
    • C) It remains the same
    • D) It is quadrupled

    Answer: It is doubled

    Explanation: Period = 2πr / v. When r is doubled and v remains constant, period is doubled, as it is directly proportional to r.