A particle is moving in a circular path. If its speed is doubled and radius is halved, what happens to its centripetal acceleration?
Q1. A particle is moving in a circular path. If its speed is doubled and radius is halved, what happens to its centripetal acceleration?
Answer: It is increased by 8 times
Explanation: New a_c = (2v)² / (r/2) = 8 * (v² / r) = 8 * a_c, using the formula a_c = v² / r.