A stone is tied to a string and whirled in a horizontal circular path. If the string is 1 m long, what is the time period of the stone if it completes 10 revolutions in 20 s?
Q1. A stone is tied to a string and whirled in a horizontal circular path. If the string is 1 m long, what is the time period of the stone if it completes 10 revolutions in 20 s?
Answer: 2 s
Explanation: Time period (T) = Total time / Number of revolutions = 20 / 10 = 2 s.