A cyclist is moving on a circular track with a radius of 30 m. If his centripetal acceleration is 3 m/s², what is his speed?
Q1. A cyclist is moving on a circular track with a radius of 30 m. If his centripetal acceleration is 3 m/s², what is his speed?
Answer: 9 m/s
Explanation: Speed (v) = √(a_c * r) = √(3 * 30) = 9.48 ≈ 9 m/s, using the formula a_c = v² / r.