engineering physics MCQ #919

The potential difference between two points is 20 V. If the distance between them is 2 m, the electric field is

engineering physics MCQ #919

  1. Question 1

    Q1. The potential difference between two points is 20 V. If the distance between them is 2 m, the electric field is

    • A) 40 N/C
    • B) 10 N/C
    • C) 20 N/C
    • D) 5 N/C

    Answer: 10 N/C

    Explanation: Using E = V / d, where V = 20 V, d = 2 m, we get E = 20 / 2 = 10 N/C