A wire of resistance 4 ohm is stretched to twice its original length. Its new resistance is
Q1. A wire of resistance 4 ohm is stretched to twice its original length. Its new resistance is
Answer: 16 ohm
Explanation: Using R = ρl / A, when l is doubled and A is halved, R becomes 4 times, hence new R = 4 * 4 = 16 ohm