The resistivity of a material is 1.7 * 10^-8 ohm-m at 20°C. If its temperature coefficient is 0.0039 /°C, its resistivity at 100°C is
Q1. The resistivity of a material is 1.7 * 10^-8 ohm-m at 20°C. If its temperature coefficient is 0.0039 /°C, its resistivity at 100°C is
Answer: 2.28 * 10^-8 ohm-m
Explanation: Using ρ = ρ0 (1 + α(T - T0)), where ρ0 = 1.7 * 10^-8, α = 0.0039, T = 100, T0 = 20, we get ρ = 1.7 * 10^-8 (1 + 0.0039 * 80) = 2.28 * 10^-8 ohm-m