A cell of emf 2 V and internal resistance 1 ohm is connected to an external resistance of 4 ohm. The current is
Q1. A cell of emf 2 V and internal resistance 1 ohm is connected to an external resistance of 4 ohm. The current is
Answer: 0.4 A
Explanation: Using I = E / (R + r), where E = 2, R = 4, r = 1, we get I = 2 / (4 + 1) = 0.4 A