The time taken by a 5 ohm resistor to dissipate 100 J of energy when a current of 2 A flows through it is
Q1. The time taken by a 5 ohm resistor to dissipate 100 J of energy when a current of 2 A flows through it is
Answer: 5 s
Explanation: Using E = I²Rt, where E = 100, I = 2, R = 5, we get 100 = 2² * 5 * t, hence t = 100 / (4 * 5) = 5 s