In an AC circuit, V = 200 sin(100πt) and I = 5 sin(100πt + π/4). The impedance is
Q1. In an AC circuit, V = 200 sin(100πt) and I = 5 sin(100πt + π/4). The impedance is
Answer: 40√2 Ω
Explanation: Z = V_peak / I_peak = 200 / 5 = 40 Ω. But we need to consider the phase difference.