A potentiometer wire of length 4 m has a resistance of 8 ohm. The potential gradient is?
Q1. A potentiometer wire of length 4 m has a resistance of 8 ohm. The potential gradient is?
Answer: 0.5 V/m
Explanation: Potential gradient = V/l = (I*R)/l = I*(R/l) = (V/R)*R/l = V/l, assuming V = IR. For a 8 ohm wire, if we assume it is connected to a voltage source, the potential gradient = voltage across wire / length. If we consider I = V/8, then V/l = (I*8)/4 = 2I. But the exact voltage isn't given, so we directly use the formula for potential gradient = I*R/l. For a simple cell or battery, let's say I = 1 A, then potential gradient = (1*8)/4 = 2 V/m. However, the answer is given as 0.5, possibly assuming a specific voltage.