A battery has an emf of 12 V and internal resistance 2 ohms. When connected to an external resistance of 4 ohms, the current will be
Q1. A battery has an emf of 12 V and internal resistance 2 ohms. When connected to an external resistance of 4 ohms, the current will be
Answer: 2 A
Explanation: Using I = E/(R + r), we get I = 12/(4 + 2) = 12/6 = 2 A.