A wire of resistance 5 ohms is stretched to twice its length. The new resistance is
Q1. A wire of resistance 5 ohms is stretched to twice its length. The new resistance is
Answer: 20 ohms
Explanation: When the wire is stretched to twice its length, its area becomes half, so R = ρ(2l)/(A/2) = 4ρl/A = 4*5 = 20 ohms.