A battery of emf 12 V and internal resistance 2 ohm is connected to a resistor. If the current in the circuit is 0.5 A, the resistance of the resistor is?
Q1. A battery of emf 12 V and internal resistance 2 ohm is connected to a resistor. If the current in the circuit is 0.5 A, the resistance of the resistor is?
Answer: 22 ohm
Explanation: Using I = E / (R + r), we have 0.5 = 12 / (R + 2). So, R + 2 = 24, R = 22 ohm.