The current in a circuit with a battery of emf 10 V and internal resistance 1 ohm is 2 A. The potential difference across the terminals of the battery is?
Q1. The current in a circuit with a battery of emf 10 V and internal resistance 1 ohm is 2 A. The potential difference across the terminals of the battery is?
Answer: 8 V
Explanation: V = E - Ir = 10 - 2 * 1 = 8 V.