The emf of a cell is 2 V and its internal resistance is 1 ohm. When it is connected to an external resistance of 4 ohm, the current is?
Q1. The emf of a cell is 2 V and its internal resistance is 1 ohm. When it is connected to an external resistance of 4 ohm, the current is?
Answer: 0.4 A
Explanation: I = E / (R + r) = 2 / (4 + 1) = 0.4 A.