A 5 Ω and a 10 Ω resistor are in series across an ideal 30 V battery. What is the current?
Q1. A 5 Ω and a 10 Ω resistor are in series across an ideal 30 V battery. What is the current?
Answer: 2 A
Explanation: In a series circuit, total resistance = 5 + 10 = 15 Ω, and by Ohm's law I = V/R = 30/15 = 2 A. The same 2 A flows through both resistors since they are in series.