general math MCQ #1200

I. x² - x - 42 = 0, II. y² - 17y + 72 = 0 to solve both the equations to find the values of x and y?

general math MCQ #1200

  1. Question 1

    Q1. I. x² - x - 42 = 0, II. y² - 17y + 72 = 0 to solve both the equations to find the values of x and y?

    • A) If x < y
    • B) If x > y
    • C) If x ≤ y
    • D) If x ≥ y

    Answer: If x < y

    Explanation: Solving: x = 7 or x = −6; y = 8 or 9. In all cases x < y.