The sum of five consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?
Q1. The sum of five consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?
Answer: 240
Explanation: Set x has middle value 440/5 = 88, so least = 84; second least of new set = 2×84 − 121 = 47, making the least 46; sum of five consecutive integers from 46 = 240.