If x varies directly as (4y-1), and x = 14 when y = 2, what is the value of x when y = 5?
Q1. If x varies directly as (4y-1), and x = 14 when y = 2, what is the value of x when y = 5?
Answer: 38
Explanation: x varies directly as (4y−1): x = k(4y−1). When y=2, x=14 → k=2. When y=5: x = 2×(20−1) = 2×19 = 38.