general math MCQ #1635

I. 9a² + 18a + 5 = 0, II. 2b² + 13b + 20 = 0 to solve both the equations to find the values of a and b?

general math MCQ #1635

  1. Question 1

    Q1. I. 9a² + 18a + 5 = 0, II. 2b² + 13b + 20 = 0 to solve both the equations to find the values of a and b?

    • A) If a > b
    • B) If a ≥ b
    • C) If a < b
    • D) If a ≤ b

    Answer: If a > b

    Explanation: Solving 9a²+18a+5=0 gives a = -1/3 or -5/3; solving 2b²+13b+20=0 gives b = -5/2 or -4. Since a's values (-0.33, -1.67) are greater than b's values (-2.5, -4), a > b.