Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?
Q1. Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?
Answer: 6
Explanation: The required number divides all differences: 215−47=168, 365−215=150. GCD(168, 150) = 6.