general math MCQ #1786

I. a² - 13a + 42 = 0, II. b² - 15b + 56 = 0 to solve both the equations to find the values of a and b?

general math MCQ #1786

  1. Question 1

    Q1. I. a² - 13a + 42 = 0, II. b² - 15b + 56 = 0 to solve both the equations to find the values of a and b?

    • A) If a > b
    • B) If a ≥ b
    • C) If a < b
    • D) If a ≤ b.

    Answer: If a ≤ b.

    Explanation: Equation I gives a = 6 or 7; Equation II gives b = 7 or 8; in every combination a ≤ b, so a ≤ b.