What is the smallest number, which when divided by 3,8 and 15 leaves the remainder 1,6,13 respectively?
Q1. What is the smallest number, which when divided by 3,8 and 15 leaves the remainder 1,6,13 respectively?
Answer: 118
Explanation: The deficit (divisor−remainder) is constant at 2 for each divisor. LCM(3,8,15) = 120. Answer = 120−2 = 118.