Find the least number which when divide by 2, 3, 4, 5 and 6 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 7 leaves no remainder?
Q1. Find the least number which when divide by 2, 3, 4, 5 and 6 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 7 leaves no remainder?
Answer: 119
Explanation: LCM(2,3,4,5,6) = 60; numbers of the form 60k−1 that are divisible by 7: 60×2−1 = 119 = 7×17.