There are two identical red, two identical black, and two identical white balls.In how many different ways can the balls be placed in the cells (Each cell to contain one ball) such that balls of the same colour do not occupy any two consecutive cells?
Q1. There are two identical red, two identical black, and two identical white balls.In how many different ways can the balls be placed in the cells (Each cell to contain one ball) such that balls of the same colour do not occupy any two consecutive cells?
Answer: 30
Explanation: Total arrangements of 2R,2B,2W = 6!/(2!2!2!) = 90; valid arrangements with no two same-color adjacent = 30.