The age of a father is twice that of the elder son. Ten years hence the age of the father will be three times of that of the younger son. If the difference of ages of the two sons is 15 years, the age of the father is:
Q1. The age of a father is twice that of the elder son. Ten years hence the age of the father will be three times of that of the younger son. If the difference of ages of the two sons is 15 years, the age of the father is:
Answer: 50 years
Explanation: Let the younger son's age be y; elder son = y+15, father = 2(y+15). In 10 years the father is 3 times the younger son: 2y+40 = 3y+30, giving y = 10 and father's age = 50.