In how many different ways can six players be arranged in a line such that two of them, Asim and Raheem are never together?
Q1. In how many different ways can six players be arranged in a line such that two of them, Asim and Raheem are never together?
Answer: 480
Explanation: Total arrangements of 6 players = 6! = 720. Treating Asim and Raheem as one unit gives 5! × 2! = 240 arrangements where they are together. Arrangements where they are never together = 720 − 240 = 480.