A is two years older than B, who is twice as old as C. If the sum of the ages of A, B, and C is 27, how old is B?
Q1. A is two years older than B, who is twice as old as C. If the sum of the ages of A, B, and C is 27, how old is B?
Answer: 10 years
Explanation: Setting C = x: B = 2x, A = 2x + 2; total = 5x + 2 = 27 → x = 5, so B = 10 years.