What is the perimeter of a square field whose diagonal is 8√2?
Question 1
Q1. What is the perimeter of a square field whose diagonal is 8√2?
Answer: 32 m
Explanation: For a square with diagonal d, side = d/√2 = 8√2/√2 = 8 m. Perimeter = 4 × 8 = 32 m.