The radius of a wire is decreased to one -third if volume remains the same length will increase:
Q1. The radius of a wire is decreased to one -third if volume remains the same length will increase:
Answer: 9 times
Explanation: Volume = πr²l is constant. With new radius r/3: π(r/3)²l' = πr²l, so l' = 9l. The length increases 9 times.