Find the value of x when y = 5, if x varies directly as 4y-1 and x = 14 when y = 2. Proportion
Q1. Find the value of x when y = 5, if x varies directly as 4y-1 and x = 14 when y = 2. Proportion
Answer: 38
Explanation: x ∝ (4y − 1): when y = 2, 4y−1 = 7 and x = 14, giving constant k = 2; when y = 5, x = 2 × (4×5−1) = 38.