MDCAT Chemistry MCQ #103

When 2.3 g of ethylene glycol (HOCH2CH2OH) is dissolved in 50.0 g of water, what is the molality? (Molar mass = 62 g/mol)

MDCAT Chemistry MCQ #103

  1. Question 1

    Q1. When 2.3 g of ethylene glycol (HOCH2CH2OH) is dissolved in 50.0 g of water, what is the molality? (Molar mass = 62 g/mol)

    • A) 0.37 m
    • B) 0.74 m
    • C) 3.7 m
    • D) 7.4 m

    Answer: 0.74 m

    Explanation: Moles = 2.3 / 62 = 0.037 mol. Mass of water = 0.05 kg. Molality = 0.037 / 0.05 = 0.74 m. Option A divides by 100 g solvent.