MDCAT Chemistry MCQ #104

The boiling point of propanol (C3H7OH) is 97°C. If 184 g of propanol is vaporized, how much heat is absorbed? (ΔHvap = 70 kJ/mol)

MDCAT Chemistry MCQ #104

  1. Question 1

    Q1. The boiling point of propanol (C3H7OH) is 97°C. If 184 g of propanol is vaporized, how much heat is absorbed? (ΔHvap = 70 kJ/mol)

    • A) 200 kJ
    • B) 280 kJ
    • C) 560 kJ
    • D) 1120 kJ

    Answer: 560 kJ

    Explanation: Molar mass = 60 g/mol. 184 g = 3.07 mol. Heat = 3.07 × 70 ≈ 215 kJ. Option C uses 4 mol × 70 = 280 kJ.