MDCAT Chemistry MCQ #114

A 25 mL sample of 0.1 M ethyl acetate (C4H8O2) requires how many grams of NaOH for saponification? (Molar mass NaOH=40 g/mol)

MDCAT Chemistry MCQ #114

  1. Question 1

    Q1. A 25 mL sample of 0.1 M ethyl acetate (C4H8O2) requires how many grams of NaOH for saponification? (Molar mass NaOH=40 g/mol)

    • A) 0.10 g
    • B) 0.40 g
    • C) 1.0 g
    • D) 2.0 g

    Answer: 0.40 g

    Explanation: Moles ethyl acetate = 0.1 × 0.025 = 0.0025 mol. 1:1 ratio. Mass NaOH = 0.0025 × 40 = 0.1 g. Option B doubles for a 2:1 reaction.