MDCAT Chemistry MCQ #1748

A molecule of Hydrogen Fluoride (HF) has a bond length of 91.7 pm and a dipole moment of 1.91 D. Calculate the charge in units of 10^-10 esu.

MDCAT Chemistry MCQ #1748

  1. Question 1

    Q1. A molecule of Hydrogen Fluoride (HF) has a bond length of 91.7 pm and a dipole moment of 1.91 D. Calculate the charge in units of 10^-10 esu.

    • A) 2.08
    • B) 1.91
    • C) 4.80
    • D) 0.48

    Answer: 2.08

    Explanation: HF dipole moment is 1.91 D; dividing this by the bond length in cm (0.917e-8) yields 2.08e-10 esu. 4.80 is the electronic charge.