MDCAT Chemistry MCQ #2209

The molar solubility of Lead (II) chloride (PbCl2) in water is 0.01 mol/dm³ at 25°C. What is the calculated solubility product (Ksp) for this salt?

MDCAT Chemistry MCQ #2209

  1. Question 1

    Q1. The molar solubility of Lead (II) chloride (PbCl2) in water is 0.01 mol/dm³ at 25°C. What is the calculated solubility product (Ksp) for this salt?

    • A) 1 × 10⁻⁴
    • B) 4 × 10⁻⁶
    • C) 2 × 10⁻⁶
    • D) 4 × 10⁻⁴

    Answer: 4 × 10⁻⁶

    Explanation: Ksp for PbCl2 = 4s³; substituting s = 0.01 gives 4 * (10⁻²)³ = 4 × 10⁻⁶. Option A incorrectly uses the s² formula for AB type salts.