An acidic buffer is prepared using 0.1 M sodium acetate and 0.01 M acetic acid (pKa = 4.74). What is the pH of the resulting buffer?
Q1. An acidic buffer is prepared using 0.1 M sodium acetate and 0.01 M acetic acid (pKa = 4.74). What is the pH of the resulting buffer?
Answer: 5.74
Explanation: pH = pKa + log([Salt]/[Acid]); pH = 4.74 + log(0.1/0.01) = 4.74 + 1 = 5.74. Option A is just the pKa without the log ratio.