According to the PTB textbook, what is the value of the ionic product of water (Kw) at exactly 25°C?
Q1. According to the PTB textbook, what is the value of the ionic product of water (Kw) at exactly 25°C?
Answer: 1.0 × 10⁻ⁱ⁴ mol²dm⁻⁶
Explanation: At 25°C, Kw = [H+][OH-] = 10⁻¹⁴. Option B is the pKw value, which is the negative log, not the product itself.