MDCAT Chemistry MCQ #2213

Calculate the molar solubility of AgCl (Ksp = 1.0 × 10⁻ⁱ⁰) in a 0.1 M solution of Sodium Chloride (NaCl) at 25°C.

MDCAT Chemistry MCQ #2213

  1. Question 1

    Q1. Calculate the molar solubility of AgCl (Ksp = 1.0 × 10⁻ⁱ⁰) in a 0.1 M solution of Sodium Chloride (NaCl) at 25°C.

    • A) 1.0 × 10⁻⁵ mol/dm³
    • B) 1.0 × 10⁻⁹ mol/dm³
    • C) 1.0 × 10⁻ⁱⁱ mol/dm³
    • D) 1.0 × 10⁻ⁱ⁰ mol/dm³

    Answer: 1.0 × 10⁻⁹ mol/dm³

    Explanation: Common ion effect: [Cl-] ≈ 0.1 M from NaCl. Ksp = [Ag+][Cl-] → 10⁻ⁱ⁰ = [Ag+](0.1) → [Ag+] = 10⁻⁹. Option A ignores the NaCl concentration.