A 0.1 M solution of a weak monobasic acid has a Ka of 1.0 × 10⁻⁵. What is the pH of this solution?
Q1. A 0.1 M solution of a weak monobasic acid has a Ka of 1.0 × 10⁻⁵. What is the pH of this solution?
Answer: 3
Explanation: For a weak acid, [H+] = √(Ka × C) = √(10⁻⁵ × 0.1) = 10⁻³. Thus pH = 3. Option A assumes the acid is strong and fully dissociates.