Calculate the percentage ionization of a 0.1 M Ammonia (NH3) solution, given that its base dissociation constant Kb is 1.8 × 10⁻⁵.
Q1. Calculate the percentage ionization of a 0.1 M Ammonia (NH3) solution, given that its base dissociation constant Kb is 1.8 × 10⁻⁵.
Answer: 1.34%
Explanation: Degree of ionization α = √(Kb/C) = √(1.8 × 10⁻⁵ / 0.1) = √(1.8 × 10⁻⁴) ≈ 0.0134 or 1.34%. Option A is the value of Kb itself.