A specific weak acid has a Ka value of 1.0 × 10⁻⁵. What is the pKb value of its conjugate base at 25°C?
Q1. A specific weak acid has a Ka value of 1.0 × 10⁻⁵. What is the pKb value of its conjugate base at 25°C?
Answer: 9
Explanation: pKa = -log(Ka) = -log(10⁻⁵) = 5. pKb = 14 - pKa = 14 - 5 = 9. Option A is the pKa value.