For a multi-step reversible reaction, how is the equilibrium constant Kc related to the rate constants of the forward and reverse elementary steps?
Q1. For a multi-step reversible reaction, how is the equilibrium constant Kc related to the rate constants of the forward and reverse elementary steps?
Answer: The ratio of the forward and backward rate constants
Explanation: Kc is the ratio of rate constants of elementary steps (kf/kr). Option D is wrong because Kc is independent of the path.