A solution is prepared by dissolving 12 g of urea (molar mass = 60 g/mol) in 1000 g of water. What is the molality of the solution?
Q1. A solution is prepared by dissolving 12 g of urea (molar mass = 60 g/mol) in 1000 g of water. What is the molality of the solution?
Answer: 0.2 m
Explanation: Molality = moles of solute / kg of solvent. 12/60 = 0.2 mol in 1 kg. Option D ignores kg of solvent.