A gas at 2 atm and 300 K occupies 10 L. What is its volume at 3 atm and 600 K? (R = 0.0821 L·atm/mol·K)
Q1. A gas at 2 atm and 300 K occupies 10 L. What is its volume at 3 atm and 600 K? (R = 0.0821 L·atm/mol·K)
Answer: 10 L
Explanation: Using PV/T = constant: (2×10)/300 = (3×V)/600 → V = 10 L. Option A misapplies gas law ratios.