What is the molarity of a 30 mL HCl solution that neutralizes 20 mL of 0.15 M NaOH?
Q1. What is the molarity of a 30 mL HCl solution that neutralizes 20 mL of 0.15 M NaOH?
Answer: 0.1 M
Explanation: M₁V₁ = M₂V₂ → M₁ = (0.15×20)/30 = 0.1 M. Option C swaps volumes.